【leetcode】27. Remove Element

题目

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

代码

#include <algorithm>#include <iostream>#include <vector>using namespace std;int main(int argc, char *argv[]) {  int A[]={4,5};  int n=2;  int elem=4;  int count=0;  for(int i=0;i<n;++i) {    if(A[i]!=elem) {      A[count++]=A[i];                cout<<A[i]<<",";    }  }  return count;}