Leetcode Problem.58—Length of Last Word
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Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
My C++ solution!
int lengthOfLastWord(string s) { int len=s.length(); int pos=0; int count=0; if(len==0) return 0; while(pos<len){if(s[pos]!=32){count++; pos++;}else{while(pos<len&&s[pos]==32)pos++; if(pos<len) { count=1; pos++; }}} return count; }
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