a letter and a number

a letter and a number

时间限制：3000 ms  |  内存限制：65535 KB

难度：1

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6R 1P 2G 3r 1p 2g 3

样例输出

191810-17-14-4

上传者

苗栋栋

#include<stdio.h>
int main()
{
    int k;
    scanf("%d",&k);
    getchar();
    while(k--)
    {

        char zw;
        int j,sum=0;
        scanf("%c %d",&zw,&j);
        if(zw>='A'&&zw<='Z')
           {sum+=(zw-64);}
        else
            {sum+=(96-zw);}            //是96-zw；
        sum=sum+j;
        printf("%d\n",sum);
        getchar();                            //绝不能少；
    }
}