Q

Description

Given a list of monetary amounts in a standard format, please calculate the total amount.

We define the format as follows:

1. The amount starts with '$'.

2. The amount could have a leading '0' if and only if it is less then 1.

3. The amount ends with a decimal point and exactly 2 following digits.

4. The digits to the left of the decimal point are separated into groups of three by commas (a group of one or two digits may appear on the left).

Input

The input consists of multiple tests. The first line of each test contains an integer N (1 <= N <= 10000) which indicates the number of amounts. The next N lines contain N amounts. All amounts and the total amount are between $0.00 and $20,000,000.00, inclusive. N=0 denotes the end of input.

Output

For each input test, output the total amount.

Sample Input

2
$1,234,567.89
$9,876,543.21
3
$0.01
$0.10
$1.00
0

Sample Output

$11,111,111.10
$1.11

题意：

就是求出相加之和

分析：

先用字符串输入，然后转化成int类型进行加减

代码：

#include<bits/stdc++.h>using namespace std;int main(){    int n,v[100],w[100],longs,t,i,j,m,x;    string a;    while(cin>>n&&n)    {        memset(v,0,sizeof(v));        memset(w,0,sizeof(w));        longs=0;        for(i=0;i<n;i++)        {            cin>>a;            t=a.size();            for(j=t-1,m=1;j>=0;j--)                if(a[j]>='0'&&a[j]<='9'){                    v[m]=a[j]-'0';                    m++;                }            longs=max(longs,m);            for(j=1,x=0;j<longs;j++){                w[j]+=x+v[j];                x=w[j]/10;                w[j]=w[j]%10;                v[j]=0;            }            if(x>0){                w[j]=x;                longs++;            }        }        cout<<"$";        for(i=longs-1;i>0;i--){            if(i%3==2&&i!=2&&i!=longs-1)            cout<<",";            if(i==2)            cout<<".";            cout<<w[i];        }        cout<<endl;    }}

感受：

就是麻烦，麻烦