用vc++实现IFS分形算法画一棵树

来源：互联网发布：java线程安全的集合编辑：程序博客网时间：2024/06/11 03:31

void IFS(){double a[][8]={0,0.195,-0.488 ,0.344 ,0.433 ,0.4431 ,0.2452 ,0.25 ,\0,0.462 ,0.414 ,-0.252 ,0.361 ,0.2511 ,0.5692 ,0.25,\0,-0.058 ,-0.07 ,0.453 ,-0.111 ,0.5976 ,0.0969 ,0.25 ,\0,-0.035 ,0.07 ,-0.469 ,-0.022 ,0.4884 ,0.5069 ,0.2,\0,-0.637 ,0 ,0 ,0.501 ,0.8562 ,0.2513 ,0.05};double aa,bb;aa = a[0][1];double x = 900;srand( (unsigned)time( NULL ) );double x0,y0;x0=0;y0=0;initgraph(1000,1000);//setorigin(getwidth() / 2, getheight() / 2);         // 设置坐标原点为窗口中心for (int k=0;k<10000;k++){int r = rand()%100;double x1,y1;if(r<=25){x1 = a[0][1]*x0+a[0][2]*y0+a[0][5];y1 = a[0][3]*x0+a[0][4]*y0+a[0][6];}else if(r<=50){x1 = a[1][1]*x0+a[1][2]*y0+a[1][5];y1 = a[1][3]*x0+a[1][4]*y0+a[1][6];}else if (r<=75){x1 = a[2][1]*x0+a[2][2]*y0+a[2][5];y1 = a[2][3]*x0+a[2][4]*y0+a[2][6];}else if (r<=95){x1 = a[3][1]*x0+a[3][2]*y0+a[3][5];y1 = a[3][3]*x0+a[3][4]*y0+a[3][6];}else{x1 = a[4][1]*x0+a[4][2]*y0+a[4][5];y1 = a[4][3]*x0+a[4][4]*y0+a[4][6];}x0 = x1;y0 = y1;putpixel(x1*x,1000-y1*x,HSLtoRGB(200,r*6,200));}getch();closegraph();}

用到了www.easyx.cn

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