数组作为函数参数

数组交换：

#include <iostream>using namespace std;void changge(int a,int b){int temp;//a,b互换 temp=a; a=b; b=temp; }int main(int argc, char** argv) {int a[]={1,2,3,4,5,6,7,8};int b[]={-1,-2,-3,-4,-5,-6,-7,-8};int i;for(i=0;i<8;i++){changge(a[i],b[i]);}for(i=0;i<8;i++){cout<<a[i]<<" "<<b[i]<<" ";} return 0;}

      有运行结果可以看出，虽然changge函数中a和b的值交换了，但最后打印的结果并没有变，这说明参数的值是单向传递。

改进：

#include <iostream>using namespace std;void changge(int x[],int y[]){int temp,i;for(i=0;i<8;i++){temp=x[i];x[i]=y[i];y[i]=temp;}}int main(int argc, char** argv) {int a[]={1,2,3,4,5,6,7,8};int b[]={-1,-2,-3,-4,-5,-6,-7,-8};int i;changge(a,b);for(i=0;i<8;i++){cout<<a[i]<<" "<<b[i]<<" ";}/*for(i=0;i<8;i++){changge(a[i],b[i]);}for(i=0;i<8;i++){cout<<a[i]<<" "<<b[i]<<" ";} */return 0;}