poj 1000 入门题

A+B Problem

Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 412305 Accepted: 231456

Description

Calculate a+b

Input

Two integer a,b (0<=a,b<=10)

Output

Output a+b

Sample Input

1 2

Sample Output

3

Hint

Q: Where are the input and the output? 

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. 

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". 

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so. 

Here is a sample solution to problem 1000 using C++/G++: 

#include <iostream>using namespace std;int main(){    int a,b;    cin >> a >> b;    cout << a+b << endl;    return 0;}

It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. 

Here is a sample solution to problem 1000 using C/GCC: 

#include <stdio.h>int main(){    int a,b;    scanf("%d %d",&a, &b);    printf("%d\n",a+b);    return 0;}

Here is a sample solution to problem 1000 using Pascal: 

program p1000(Input,Output);var  a,b:Integer;begin   Readln(a,b);   Writeln(a+b);end.

Here is a sample solution to problem 1000 using Java: 

Now java compiler is jdk 1.5, next is program for 1000 

import java.io.*;import java.util.*;public class Main{            public static void main(String args[]) throws Exception            {                    Scanner cin=new Scanner(System.in);                    int a=cin.nextInt(),b=cin.nextInt();                    System.out.println(a+b);            }}

Old program for jdk 1.4 

import java.io.*;import java.util.*;public class Main{    public static void main (String args[]) throws Exception    {        BufferedReader stdin =             new BufferedReader(                new InputStreamReader(System.in));        String line = stdin.readLine();        StringTokenizer st = new StringTokenizer(line);        int a = Integer.parseInt(st.nextToken());        int b = Integer.parseInt(st.nextToken());        System.out.println(a+b);    }}

Here is a sample solution to problem 1000 using Fortran: 

PROGRAM P1000IMPLICIT NONEINTEGER :: A, BREAD(*,*) A, BWRITE(*, "(I0)") A + BEND PROGRAM P1000

Source

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ac代码

#include <stdio.h>int main(){int a,b,ans;while(~scanf("%d%d",&a,&b)){ans=a+b;printf("%d\n",ans);}return 0;}