PAT-A 1006. Sign In and Sign Out (25)
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题目链接在此。
题意
求最早、最晚到的人。
思路
结合下面的代码,参考这题思路。
AC代码
#include<stdio.h>#include<string.h>int main(){ char unlock[16], lock[16], temp[16]; int M; int hh1,mm1,ss1,hh2,mm2,ss2; long long time1,time2; long long earliest = 246060, lastest = 000000; scanf("%d",&M); for(int i = 0; i < M; i++){ scanf("%s %d:%d:%d %d:%d:%d",&temp,&hh1,&mm1,&ss1,&hh2,&mm2,&ss2); time1 = hh1*10000+mm1*100+ss1; time2 = hh2*10000+mm2*100+ss2; if(time1 < earliest){ earliest = time1; strcpy(unlock,temp); } if(time2 > lastest){ lastest = time2; strcpy(lock,temp); } } printf("%s %s\n",unlock,lock); return 0;}
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