Sign In and Sign Out
来源:互联网 发布:中国大数据时代 编辑:程序博客网 时间:2024/06/12 01:46
1006. Sign In and Sign Out (25)
At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to find the ones who have unlocked and locked the door on that day.
Input Specification:
Each input file contains one test case. Each case contains the records for one day. The case starts with a positive integer M, which is the total number of records, followed by M lines, each in the format:
ID_number Sign_in_time Sign_out_time
where times are given in the format HH:MM:SS, and ID number is a string with no more than 15 characters.
Output Specification:
For each test case, output in one line the ID numbers of the persons who have unlocked and locked the door on that day. The two ID numbers must be separated by one space.
Note: It is guaranteed that the records are consistent. That is, the sign in time must be earlier than the sign out time for each person, and there are no two persons sign in or out at the same moment.
Sample Input:3CS301111 15:30:28 17:00:10SC3021234 08:00:00 11:25:25CS301133 21:45:00 21:58:40
Sample Output:SC3021234 CS301133
本题的考点就是寻找最小时间和最大时间。虽然时间是字符串形式的,但是也可以按位比对来判断大小。
#include <iostream>#include <vector>#include <string>using namespace std;bool earlyTime(int index);bool lastTime(int index);vector<string> id, signIn, signOut;int unlockIndex, lockIndex;int main() {int m;cin >> m;id.resize(m);signIn.resize(m);signOut.resize(m);for (int i = 0; i < m; i++){cin >> id[i] >> signIn[i] >> signOut[i];}for (int i = 0; i < m; i++){if (earlyTime(i))unlockIndex = i;if (lastTime(i))lockIndex = i;}cout << id[unlockIndex] << " " << id[lockIndex];//system("pause");return 0;}bool earlyTime(int index) {for (int i = 0; i < 6; i++){if (signIn[index][i] < signIn[unlockIndex][i])return true;else if (signIn[index][i] > signIn[unlockIndex][i])return false;}return false;}bool lastTime(int index) {for (int i = 0; i < 6; i++){if (signOut[index][i] > signOut[lockIndex][i])return true;else if (signOut[index][i] < signOut[lockIndex][i])return false;}return false;}
- Sign In and Sign Out
- Sign In and Sign Out
- Sign In and Sign Out
- Sign In and Sign Out
- pat1006 Sign In and Sign Out
- 1006. Sign In and Sign Out (25)
- 1006. Sign In and Sign Out
- PAT1006. Sign In and Sign Out
- PAT1006. Sign In and Sign Out (25)
- PAT_1006: Sign In and Sign Out
- 1006. Sign In and Sign Out (25)
- 1006. Sign In and Sign Out (25)
- 1006 Sign In and Sign Out (25)
- 1006. Sign In and Sign Out (25)
- 1006. Sign In and Sign Out
- PAT 1006. Sign In and Sign Out
- 1006. Sign In and Sign Out (25)
- 1006. Sign In and Sign Out (25)
- 关于 supermap 发布跟踪图层后 生成的缓存模型不更变问题
- 进度
- 苹果根证书异常删除导致 App 闪退的问题
- android studio从入门到提高到精通详解。。。
- springBoot项目代码加密总结
- Sign In and Sign Out
- CNN系列
- 干货分享!深度学习几何画板绘图技巧!
- C语言再学习 -- 关键字void
- 一句代码实现标题栏、导航栏滑动隐藏。ByeBurger库的使用和实现
- <%@ Page language="c#" Codebehind="Main.aspx.cs" AutoEventWireup="false" Inherits="Vod.WebForm1" %>
- Error:Xcode cannot launch 项目名 on 设备名 because the device is locked
- sass配置一条线
- Android 阅读 Office 文档,所有你能想到的解决方案都在这啦