Codeforces Round Intel Code Challenge Final Round A.Checking the Calendar

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题目大意：问你是否存在一个非闰年，使得某个月的开始为第一行所给的星期，下一个月开始为第二行所给的星期

直接模拟即可。

或者因为每个月天数固定，所以只需要考虑特定的几种情况

#include<set>#include<map>#include<cmath>#include<queue>#include<vector>#include<cstdio>#include<string>#include<cstring>#include<iostream>#include<algorithm>using namespace std;int a[29]={0,31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};int main(){string x1,x2;cin>>x1>>x2;int xx1,xx2;if(x1[0]=='m')xx1=1;else if(x1[0]=='t'&&x1[1]=='u')xx1=2;else if(x1[0]=='w')xx1=3;else if(x1[0]=='t')xx1=4;else if(x1[0]=='f')xx1=5;else if(x1[0]=='s'&&x1[1]=='a')xx1=6;elsexx1=7;if(x2[0]=='m')xx2=1;else if(x2[0]=='t'&&x2[1]=='u')xx2=2;else if(x2[0]=='w')xx2=3;else if(x2[0]=='t')xx2=4;else if(x2[0]=='f')xx2=5;else if(x2[0]=='s'&&x2[1]=='a')xx2=6;elsexx2=7;int i,j;for(i=1;i<=11;i++){int d=xx1;for(j=1;j<=a[i];j++)d=d%7+1;if(d==xx2){printf("YES\n");return 0;}}printf("NO\n");return 0;}

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