条码(code128)的不同版本实现
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好久没写Blog了，这次写写条码（code128)打印的实现。条码在工业应用方面很广泛，所以我们在编写程序时，特别是打印报表时，经常用到。
#region "本段为转载" 转自:http://kaliking.blog.51cto.com/58641/33734
先简述一下CODE128的原理吧,分别以一个unicode字符作为起始符(Ì)和终止符(Î),
然后需要根据你的字符串, 计算出当前字符集的校验码:
ode 128 Barcode Table
Value
Code SetA
Code SetB
Code SetC
Bar/Space PatternB S B S B S
0
SP
SP
00
2 1 2 2 2 2
1
!
!
01
2 2 2 1 2 2
2
"
"
02
2 2 2 2 2 1
3
#
#
03
1 2 1 2 2 3
4
$
$
04
1 2 1 3 2 2
5
%
%
05
1 3 1 2 2 2
6
&
&
06
1 2 2 2 1 3
7
'
'
07
1 2 2 3 1 2
8
(
(
08
1 3 2 2 1 2
9
)
)
09
2 2 1 2 1 3
10
*
*
10
2 2 1 3 1 2
11
+
+
11
2 3 1 2 1 2
12
,
,
12
1 1 2 2 3 2
13
-
-
13
1 2 2 1 3 2
14
.
.
14
1 2 2 2 3 1
15
/
/
15
1 1 3 2 2 2
16
0
0
16
1 2 3 1 2 2
17
1
1
17
1 2 3 2 2 1
18
2
2
18
2 2 3 2 1 1
19
3
3
19
2 2 1 1 3 2
20
4
4
20
2 2 1 2 3 1
21
5
5
21
2 1 3 2 1 2
22
6
6
22
2 2 3 1 1 2
23
7
7
23
3 1 2 1 3 1
24
8
8
24
3 1 1 2 2 2
25
9
9
25
3 2 1 1 2 2
26
:
:
26
3 2 1 2 2 1
27
;
;
27
3 1 2 2 1 2
28
<
<
28
3 2 2 1 1 2
29
=
=
29
3 2 2 2 1 1
30
>
>
30
2 1 2 1 2 3
31
?
?
31
2 1 2 3 2 1
32
@
@
32
2 3 2 1 2 1
33
A
A
33
1 1 1 3 2 3
34
B
B
34
1 3 1 1 2 3
35
C
C
35
1 3 1 3 2 1
36
D
D
36
1 1 2 3 1 3
37
E
E
37
1 3 2 1 1 3
38
F
F
38
1 3 2 3 1 1
39
G
G
39
2 1 1 3 1 3
40
H
H
40
2 3 1 1 1 3
41
I
I
41
2 3 1 3 1 1
42
J
J
42
1 1 2 1 3 3
43
K
K
43
1 1 2 3 3 1
44
L
L
44
1 3 2 1 3 1
45
M
M
45
1 1 3 1 2 3
46
N
N
46
1 1 3 3 2 1
47
O
O
47
1 3 3 1 2 1
48
P
P
48
3 1 3 1 2 1
49
Q
Q
49
2 1 1 3 3 1
50
R
R
50
2 3 1 1 3 1
51
S
S
51
2 1 3 1 1 3
52
T
T
52
2 1 3 3 1 1
53
U
U
53
2 1 3 1 3 1
54
V
V
54
3 1 1 1 2 3
55
W
W
55
3 1 1 3 2 1
56
X
X
56
3 3 1 1 2 1
57
Y
Y
57
3 1 2 1 1 3
58
Z
Z
58
3 1 2 3 1 1
59
[
[
59
3 3 2 1 1 1
60
/
/
60
3 1 4 1 1 1
61
]
]
61
2 2 1 4 1 1
62
^
^
62
4 3 1 1 1 1
63
_
_
63
1 1 1 2 2 4
64
NUL
`
64
1 1 1 4 2 2
65
SOH
a
65
1 2 1 1 2 4
66
STX
b
66
1 2 1 4 2 1
67
ETX
c
67
1 4 1 1 2 2
68
EOT
d
68
1 4 1 2 2 1
69
ENQ
e
69
1 1 2 2 1 4
70
ACK
f
70
1 1 2 4 1 2
71
BEL
g
71
1 2 2 1 1 4
72
BS
h
72
1 2 2 4 1 1
73
HT
i
73
1 4 2 1 1 2
74
LF
j
74
1 4 2 2 1 1
75
VT
k
75
2 4 1 2 1 1
76
FF
I
76
2 2 1 1 1 4
77
CR
m
77
4 1 3 1 1 1
78
SO
n
78
2 4 1 1 1 2
79
SI
o
79
1 3 4 1 1 1
80
DLE
p
80
1 1 1 2 4 2
81
DC1
q
81
1 2 1 1 4 2
82
DC2
r
82
1 2 1 2 4 1
83
DC3
s
83
1 1 4 2 1 2
84
DC4
t
84
1 2 4 1 1 2
85
NAK
u
85
1 2 4 2 1 1
86
SYN
v
86
4 1 1 2 1 2
87
ETB
w
87
4 2 1 1 1 2
88
CAN
x
88
4 2 1 2 1 1
89
EM
y
89
2 1 2 1 4 1
90
SUB
z
90
2 1 4 1 2 1
91
ESC
{
91
4 1 2 1 2 1
92
FS
|
92
1 1 1 1 4 3
93
GS
}
93
1 1 1 3 4 1
94
RS
~
94
1 3 1 1 4 1
95
US
DEL
95
1 1 4 1 1 3
96
FNC 3
FNC 3
96
1 1 4 3 1 1
97
FNC 2
FNC 2
97
4 1 1 1 1 3
98
SHIFT
SHIFT
98
4 1 1 3 1 1
99
CODE C
CODE C
99
1 1 3 1 4 1
100
CODE B
FNC 4
CODE B
1 1 4 1 3 1
101
FNC 4
CODE A
CODE A
3 1 1 1 4 1
102
FNC 1
FNC 1
FNC 1
4 1 1 1 3 1
103
Start A
Start A
Start A
2 1 1 4 1 2
104
Start B
Start B
Start B
2 1 1 2 1 4
105
Start C
Start C
Start C
2 1 1 2 3 2
106
Stop
Stop
Stop
2 3 3 1 1 1 2
Example... To calculate the check digit for the barcode data string 'Code 128'
Value Total ===== ===== Start Code B 104 104Position 1 C 35 1 x 35 = 35Position 2 o 79 2 x 79 = 158Position 3 d 68 3 x 68 = 204Position 4 e 69 4 x 69 = 276Position 5 0 5 x 0 = 0Position 6 1 17 6 x 17 = 102Position 7 2 18 7 x 18 = 126Position 8 8 24 8 x 24 = 192 ===== 1197 ===== 1197/103 = 11 remainder 64 根据上表, 把没个字符的value值 乘上 字符在字符串中的位置(从1开始算)把没个乘积加起来因为CODESET B 为104(这是规定, 不要问我为什么)所以, 还要加上 104 最后, 除以103, 所得的余数就是 校验码 的value值, 然后在表中找到对应的字符就可以了. 有心人应该注意到了, value>=95的时候, 是没有字符的(事实上还是有的, 只不过是unicode字符)好了, 原理就阐述到这里, 还有什么不懂的话, 大家看看代码好了.至于用在水晶报表上的问题, 我这里是配合条码字体的, 我会上传一个我正在用的字体.代码如下:Public Function StringToCode128(ByVal input As String) As String Try Dim endchar As Char Dim total As Int64 = 104 Dim tmp As Integer For i As Int16 = 1 To input.Length tmp = Asc(input.Substring(i - 1, 1)) If tmp >= 32 Then total += (tmp - 32) * i Else total += (tmp + 64) * i End If Next Dim endAsc = total Mod 103 If endAsc >= 95 Then Select Case endAsc Case 95 endchar = "Ã" Case 96 endchar = "Ä" Case 97 endchar = "Å" Case 98 endchar = "Æ" Case 99 endchar = "Ç" Case 100 endchar = "È" Case 101 endchar = "É" Case 102 endchar = "Ê" End Select Else endAsc += 32 endchar = Chr(endAsc) End If Return "Ì" & input & endchar.ToString() & "Î" Catch ex As Exception WriteLog(ex.Message, ex.StackTrace) Return String.Empty Finally End Try End Function我放大一下上面用到的特殊字符,大家看看清楚:起始符:Ì终止符:Îvalue95:Ã value96:Ä value97:Å value98:Æ value99:Ç value100:È value101:É value102:Ê#endregion根据以上代码，这作了几个转换的版本，用于不同的环境，C#版本： private string StringToCode128(string input) { try { char endChar=(char)0; Int64 total = 104; int tmp; Int64 endAsc; for (int i = 0; i < input.Length; i++) { tmp = (int)(Convert.ToChar(input.Substring(i, 1))); if (tmp >= 32) { total += (tmp - 32) * (i + 1); } else { total += (tmp + 64) * (i + 1); } } endAsc = total % 103; if (endAsc >= 95) { switch (endAsc) { case 95: endChar = 'Ã'; break; case 96: endChar = 'Ä'; break; case 97: endChar = 'Å'; break; case 98: endChar = 'Æ'; break; case 99: endChar = 'Ç'; break; case 100: endChar = 'È'; break; case 101: endChar = 'É'; break; case 102: endChar = 'Ê'; break; } } else { endAsc += 32; endChar = (char)endAsc; } return "Ì" + input + endChar.ToString() + "Î"; } catch (Exception ex) { MessageBox.Show("Error"); return string.Empty; } }Office 中Excel版本：Public Function Code128b(DataToEncode As String) As String Dim endchar As string Dim total As Integer total = 104 Dim tmp As Integer dim i as integer dim Ito as integer Ito = Len(dataToEncode) dim tempstring as string dim j as integer For i = 1 To Ito tempstring = Mid(DataToEncode, i, 1) tmp = AscW(tempstring) If tmp >= 32 Then total =total+ (tmp - 32) * i Else total =total+ (tmp + 64) * i End If Next dim endasc as integer endAsc = total Mod 103 If endAsc >= 95 Then Select Case endAsc Case 95 endchar = ChrW(195) Case 96 endchar = ChrW(196) Case 97 endchar = ChrW(197) Case 98 endchar = ChrW(198) Case 99 endchar = ChrW(199) Case 100 endchar = ChrW(200) Case 101 endchar = ChrW(201) Case 102 endchar = ChrW(202) End Select Else endAsc =endasc + 32 endchar = ChrW(endAsc) End If Code128a=ChrW(204) + DataToEncode + endchar + ChrW(206)end functionOpenOffice版本（注：此版本只能在支持VBA的OxygenOffice中应用）：Public Function Code128a(DataToEncode As String) As String Dim endchar As string Dim total As Integer total = 104 Dim tmp As Integer dim i as integer dim Ito as integer Ito = Len(DataToEncode) dim tempstring as string dim j as integer For i = 1 To Ito tempstring = Mid(DataToEncode, i, 1) tmp = AscW(tempstring) If tmp >= 32 Then total =total+ (tmp - 32) * i Else total =total+ (tmp + 64) * i End If Next dim endasc as integer endAsc = total Mod 103 If endAsc >= 95 Then Select Case endAsc Case 95 endchar = "Ã" Case 96 endchar = "Ä" Case 97 endchar = "Å" Case 98 endchar = "Æ" Case 99 endchar = "Ç" Case 100 endchar = "È" Case 101 endchar = "É" Case 102 endchar = "Ê" End Select Else endAsc =endasc + 32 endchar = ChrW(endAsc) End If Code128a= "Ì" + DataToEncode + endchar + "Î"end function
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