58. Length of Last Word
来源:互联网 发布:英超直播软件 编辑:程序博客网 时间:2024/06/10 01:47
问题描述:
Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = “Hello World”,
return 5.
java代码:
public class Solution { public int lengthOfLastWord(String s) { String s1 = s.trim(); String[] ss = s1.split(" "); int length = ss.length; return ss[length-1].length(); }}
0 0
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58. Length of Last Word
- 58.Length of Last Word
- cmds纪录
- MongoDB总结(二):mongoDB的索引、备份和恢复、固定集合及数据库安全
- 消息中间件主备方案选型实践
- 南方姑娘
- Linux 环境变量 PATH 的默认值
- 58. Length of Last Word
- Mybaits配置文件生成工具
- Listener监听器
- LeetCode_8_myAtio_String to Integer
- Android-ViewPager滑动图片
- Oracle处于recover状态的数据文件是无法使用exp导出数据的
- yii2 如何在页面底部加载css和js
- 硬币问题
- Bzoj2819 Nim