【LeetCode-1】Two Sum
来源:互联网 发布:3d算法必中直选 编辑:程序博客网 时间:2024/05/19 22:59
第一次拿Python写,还不是很熟练,有点迷
class Solution(object): def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ dic = {}; for i in range(len(nums)): #这里这个用法挺精髓的,运用字典的方法进行查找下标 if target - nums[i] in dic: return [dic[target - nums[i]] + 1,i + 1] dic[nums[i]] = i
0 0
- LeetCode 1 - Two Sum
- leetcode 1 Two Sum
- Leetcode【1】:Two Sum
- [leetcode 1] Two Sum
- 【leetcode-1】Two Sum
- [leetcode 1] Two Sum
- [Leetcode] 1 - Two Sum
- LeetCode (1) Two Sum
- LeetCode 1:《Two Sum》
- LeetCode | #1 Two Sum
- leetcode-1 Two Sum
- Two Sum | LeetCode(1)
- [Leetcode]1Two Sum
- leetcode 1 Two Sum
- leetcode #1 Two Sum
- leetcode 1:Two Sum
- LeetCode 1 Two Sum
- leetcode #1 two sum
- 存储过程效率优化总结——杨小辉
- PowerDesign
- mybatis缓存 redis实现
- ubuntu连接windows远程桌面
- [Java] 浅谈泛型的意义与不足
- 【LeetCode-1】Two Sum
- 173.When does a transaction complete? (Choose all that apply.)
- chromium源码下载并编译
- 平均年龄-美团笔试
- tomcat Server Locations 不可用 两种解决方式
- keystore 获取(常用命令行,SDK创建应用,找应用签名的方法)
- css基础效果
- sdk23_EditText:singleLine="true"过时及引发inputType="textPassword"失效
- HTML5 表单元素