Add Two Numbers
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You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Solution:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* L = new ListNode(-1); ListNode* current = L; int flag = 0; while(l1 != NULL || l2 != NULL) { int val = flag; if(l1 != NULL) { val += l1->val; l1 = l1->next; } if(l2 != NULL) { val += l2->val; l2 = l2->next; } if(val >= 10) { val %= 10; flag = 1; } else { flag = 0; } current = current->next = new ListNode(val); } if(flag == 1) current = current->next = new ListNode(1); return L->next; }};
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