pat 1006. Sign In and Sign Out (25)
来源:互联网 发布:手持数据终端多少钱 编辑:程序博客网 时间:2024/05/29 01:52
1006. Sign In and Sign Out (25)
At the beginning of every day, the first person who signs in the computer room will unlock the door, and the last one who signs out will lock the door. Given the records of signing in's and out's, you are supposed to find the ones who have unlocked and locked the door on that day.
Input Specification:
Each input file contains one test case. Each case contains the records for one day. The case starts with a positive integer M, which is the total number of records, followed by M lines, each in the format:
ID_number Sign_in_time Sign_out_time
where times are given in the format HH:MM:SS, and ID number is a string with no more than 15 characters.
Output Specification:
For each test case, output in one line the ID numbers of the persons who have unlocked and locked the door on that day. The two ID numbers must be separated by one space.
Note: It is guaranteed that the records are consistent. That is, the sign in time must be earlier than the sign out time for each person, and there are no two persons sign in or out at the same moment.
Sample Input:3CS301111 15:30:28 17:00:10SC3021234 08:00:00 11:25:25CS301133 21:45:00 21:58:40Sample Output:
SC3021234 CS301133
代码:
#include<iostream>#include<cstdlib>#include<cstdio>using namespace std;struct person{ string id; string time1,time2; int t1,t2;};int main(){ int num; while(scanf("%d",&num)==1) { int in,out; getchar(); person *p=new person[num+1]; for(int i=0;i<num;i++) { cin>>p[i].id>>p[i].time1>>p[i].time2; p[i].t1=((p[i].time1[0]-48)*10+p[i].time1[1]-48)*3600+((p[i].time1[3]-48)*10+p[i].time1[4]-48)*60+(p[i].time1[6]-48)*10+(p[i].time1[7]-48); p[i].t2=((p[i].time2[0]-48)*10+(p[i].time2[1]-48))*3600+((p[i].time2[3]-48)*10+(p[i].time2[4]-48))*60+(p[i].time2[6]-48)*10+(p[i].time2[7]-48); } int mint=10000000,maxt=0; for(int j=0;j<num;j++) { if(p[j].t1<mint) { mint=p[j].t1; in=j; } if(p[j].t2>maxt) { maxt=p[j].t2; out=j; } } cout<<p[in].id<<" "<<p[out].id<<endl; }}
- PAT 1006. Sign In and Sign Out
- PAT 1006. Sign In and Sign Out
- 【PAT】1006. Sign In and Sign Out
- PAT-Sign In and Sign Out (25)
- 1006. Sign In and Sign Out (25)-PAT
- 【PAT】1006. Sign In and Sign Out (25)
- 【PAT Advanced Level】1006. Sign In and Sign Out (25)
- PAT 1006. Sign In and Sign Out (25)
- PAT A 1006. Sign In and Sign Out (25)
- 【PAT (Advanced Level)】1006. Sign In and Sign Out (25)
- PAT 1006. Sign In and Sign Out (25)
- PAT 1006. Sign In and Sign Out (25)
- [PAT]1006. Sign In and Sign Out (25)
- PAT 1006. Sign In and Sign Out (25)
- PAT A 1006. Sign In and Sign Out (25)
- PAT 1006. Sign In and Sign Out (25)
- pat 1006. Sign In and Sign Out (25)
- [PAT]1006. Sign In and Sign Out (25)
- POJ - 1018 Communication System (暴力)
- IOS--UI--LessonUITabBarController 标签控制器
- 2015/07/17/几个小程序
- DIV CSS 上下左右滑动
- 进制转换
- pat 1006. Sign In and Sign Out (25)
- 【转】LM(Levenberg-Marquard)算法的实现
- PROGRAMMER PRODUCTIVITY STARTS WITH REQUIREMENTS, NOT TOOLS!
- 三角形判断
- 【Ray Tracing from Ground Up】Specular Reflection
- ubuntu添加用户到root组
- windows 10 - 10240版本激活问题
- STM32W108无线射频模块AD转换器应用实例
- 数据的插入与删除