武大校赛资格赛 差值维护

Problem 1565 - B - Magic

Description

Here are n numbers.

You have a magic : first , you choose a interval [l,r],and then each Si(l<=i<=r) will be ( 10 – Si ) % 10.

You can use the magic at most once to make sum of all the numbers to be maximum.

What is the maximum sum you can get?

Input

First line of each case contains a number n.(1 ≤  n ≤ 1 000 000).

Next line contains n numbers without space-separated. Each position corresponds to a number of 0-9.

Output

Output the answer on a single line for each case.

Sample Input

10
3775053808
10
2580294019
10
4701956095

Sample Output

50
50
54

#include <iostream>#include <cstdio>#include <cstring>#include <cmath>#include <algorithm>#include <string>#include <vector>#include <set>#include <map>#include <stack>#include <queue>#include <sstream>#include <iomanip>using namespace std;typedef long long LL;const int INF = 0x4fffffff;const double EXP = 1e-5;const int MS = 1000005;const int SIZE = 100005;int num[MS];int s[MS];char str[MS];int main(){      int n;    while(cin>>n)    {        //  cin>>n;      cin>>str;      int sum=0;      int ans=0;      int total=0;    // s[0]=0;  //  int ss,tt;      for(int i=0;i<n;i++)      {            //num[i]=10-(2*(str[i]-'0'));            num[i]=(10-(str[i]-'0'))%10;            num[i]=num[i]-(str[i]-'0');          //  s[i+1]=s[i]+str[i]-'0';            total+=str[i]-'0';            if(sum<=0)            {                  sum=num[i];                  //ss=i;            }            else                  sum+=num[i];            if(sum>ans)            {                  ans=sum;                // tt=i;            }      }    // cout<<ans<<endl;      //cout<<ss<<"  "<<tt<<endl;      cout<<total+ans<<endl;    }      return 0;}