Sqrt(x)
来源:互联网 发布:红包源码 编辑:程序博客网 时间:2024/06/02 10:43
转自:http://blog.csdn.net/linhuanmars/article/details/20089131
class Solution {public: int sqrt(int x) { if(x < 0) { return -1; } if(x == 0) { return 0; } int low = 1, high = x / 2 + 1; while(low <= high) { int mid = (low + high) / 2; if(mid <= x / mid && (mid + 1) > x / (mid + 1)) { return mid; } if(mid < x / mid) { low = mid + 1; } else { high = mid - 1; } } return 0; }};
牛顿迭代法:
const double epsilon = 1e-5;class Solution {public: int sqrt(int x) { if(x < 0) { return -1; } if(x == 0) { return 0; } double last = 0; double result = 1; while(abs(result - last) > epsilon) { last = result; result = (result + x / result) / 2.0; } return result; }};
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