nyoj-94-cigarettes(香烟)
来源:互联网 发布:ubuntu命令行调整音量 编辑:程序博客网 时间:2024/06/11 17:55
cigarettes
时间限制:3000 ms | 内存限制:65535 KB
难度:2
- 描述
Tom has many cigarettes. We hypothesized that he has n cigarettes and smokes them
one by one keeping all the butts. Out of k > 1 butts he can roll a new cigarette.
Now,do you know how many cigarettes can Tom has?- 输入
- First input is a single line,it's n and stands for there are n testdata.then there are n lines ,each line contains two integer numbers giving the values of n and k.
- 输出
- For each line of input, output one integer number on a separate line giving the maximum number of cigarettes that Peter can have.
- 样例输入
34 310 3100 5
- 样例输出
514124
- 来源
- [rooot]原创
- 上传者
- rooot
- 每K个烟头可以换根新烟抽,求n根烟总共能抽几根
#include<iostream>using namespace std;int main(){ int n; cin>>n; while(n--) { int a,b; cin>>a>>b; int sum=0; sum+=a; while(a>=b) { a-=b;//只要a-b还大于b , 就相当于a会多一个 a++; sum++; } cout<<sum<<endl; } return 0;}#include "stdio.h"#include<fstream>int main(){ //freopen("d:\\1.txt","r",stdin); //freopen("d:\\2.txt","w",stdout); int m; scanf("%d",&m); while(m--) { int n,k,sum; scanf("%d%d",&n,&k); sum=n; while(n/k) { sum+=n/k; n=n/k+n%k; } printf("%d\n",sum); } return 0;}
0 0
- nyoj-94-cigarettes(香烟)
- nyoj 94 cigarettes
- nyoj-94cigarettes
- NYOJ 94 cigarettes
- nyoj 94 cigarettes
- NYOJ 题目94 cigarettes
- nyoj.94 cigarettes 20141028
- nyoj 94 cigarettes
- nyoj 94 cigarettes
- NYOJ---题目94cigarettes
- nyoj 94 cigarettes
- NYOJ 94 cigarettes
- NYOJ 94 cigarettes
- nyoj 94 cigarettes 【水题】
- 【NYOJ】[94]cigarettes
- NYOJ:94cigarettes
- NYOJ-94 cigarettes
- 【NYOJ-94】cigarettes
- ACE more --read sample
- Java Notes-4
- 邮件营销阅读人数统计访问统计
- java--this的使用
- 深入浅出的讲解傅里叶变换
- nyoj-94-cigarettes(香烟)
- No result defined for action and result input
- 程序员怎能不知道什么是数据挖掘
- java-重载,构造函数,匿名对象
- Windows常见数据类型及变量_常量命名规律
- 分支-03. 三天打鱼两天晒网(15)
- ios TableView那些事2(Swift 二) 初见TableView Grouped
- [C++] 变量、指针、引用作函数参数的区别
- UVa 10490 - Mr. Azad and his Son!!!!!