UVA 488 Triangle Wave（输出三角波）

 Triangle Wave

Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu

Description

 Triangle Wave 

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1
32

Sample Output

1
22
333
22
1
1
33
223
22

题目大意：
如图所示。
解题思路：
注意最后一行不能有空格，两组输入数据之间也要有空格。

#include<iostream>#include<cstdio>using namespace std;int n,a,b;void solve(){    for(int j=0;j<b;j++){        for(int i=1;i<=a;i++){            for(int k=1;k<=i;k++){                printf("%d",i);            }            printf("\n");        }        for(int i=a-1;i>=1;i--){            for(int k=i;k>=1;k--){                printf("%d",i);            }            printf("\n");        }        if(j!=b-1){             printf("\n");        }    }}int main(){    scanf("%d",&n);    for(int i=0;i<n;i++){        scanf("%d%d",&a,&b);        solve();        if(i!=n-1){             printf("\n");        }    }    return 0;}

代码：