hdu4706!【模拟】

来源:互联网 发布:客户管理crm软件 编辑:程序博客网 时间:2024/06/11 16:42
/*Children's DayTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 846    Accepted Submission(s): 543Problem DescriptionToday is Children's Day. Some children ask you to output a big letter 'N'. 'N' is constituted by two vertical linesand one diagonal. Each pixel of this letter is a character orderly. No tail blank is allowed.For example, this is a big 'N' start with 'a' and it's size is 3.a ebdfc gYour task is to write different 'N' from size 3 to size 10. The pixel character used is from 'a' to 'z' continuously and periodic('a' is reused after 'z').InputThis problem has no input. OutputOutput different 'N' from size 3 to size 10. There is no blank line among output.Sample Output[pre]a ebdfc gh  ni mojl pk  q.........r        j[/pre]HintNot all the resultsare listed in the sample. There are just some lines. The ellipsis expresseswhat you should write.  Source2013 ACM/ICPC Asia Regional Online —— Warmup */#include<stdio.h>#include<string.h>int main(){int i, j, k;char s[11][11], ch[26], num = 0;ch[0] = 'a';for(i = 1; i < 26; i++)ch[i] = ch[i-1] + 1;for( i = 3; i < 11;  i++){memset(s,' ',sizeof(s));k = 0;for(j = 0; j <i; j++){s[j][k] = ch[num++];if(num == 26) num = 0;}k++;for(j = i-2; j >= 0; j--, k++){s[j][k] = ch[num++];if(num == 26)num = 0;}for(j = 1; j < i; j++){s[j][k-1] = ch[num++];if(num == 26)num = 0;}for( j = 0; j < i; j++){for(k = 0; k <= i-1; k++)printf("%c",s[j][k]);printf("\n");}}return 0;}

题意:用26个小写字母排列成‘N'字形,尺寸由3*3 ~10*10,字母顺序由小到大循环使用。

思路:开一个数组模拟即可。

0 0
原创粉丝点击