103_leetcode_Single Number
来源:互联网 发布:内师大网络技术学院 编辑:程序博客网 时间:2024/06/11 16:08
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
1:xor
int singleNumber(int A[], int n) { int result = 0; for(int i = 0; i < n; i++) { result ^= A[i]; } return result; }
0 0
- 103_leetcode_Single Number
- 104_leetcode_Single NumberII
- Number
- number
- number
- Number
- number
- number
- Number
- Number
- NUMBER
- Number
- Number()
- number
- Number
- Number
- [LeetCode] 103: Single Number II
- E: number number number
- something
- 通过python调用adb命令实现用元素名称、id、class定位元素
- Netty In Action 读书笔记 - 第二章 第一个Netty应用
- eclipse调试java程序的九个技巧
- 大型网站技术架构
- 103_leetcode_Single Number
- 学习OpenCV之CV篇
- App Store 什么是IDP?
- 可靠的UDP编程
- poj 1543:Perfect Cubes
- 重回csdn
- intilij idea 13学习使用
- Kali Linux渗透测试实战 2.1
- <jsp:attribute>的用法