jquery 权限控制菜单

来源：互联网发布：曼哈顿计划知乎编辑：程序博客网时间：2024/06/10 03:09

要实现的效果：

1、父节点选中，则下面的子节点全选中

2、父节点不选中，则下面的子节点全不选中

3、子节点只要选中了一个，则父节点选中

4、子节点全不选中，则父亲节点不选中

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">    <title>My JSP 'quanxian.jsp' starting page</title>    <meta http-equiv="pragma" content="no-cache"><meta http-equiv="cache-control" content="no-cache"><meta http-equiv="expires" content="0">    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"><meta http-equiv="description" content="This is my page"><script type="text/javascript" src="js/jquery-1.11.1.js"></script><script type="text/javascript">function selectAll(idStart){var x = $("input[id^='"+idStart+"']");x.each(function(index,domEle){$(this).prop("checked",true);});}function unSelectAllBox(idStart){var x = $("input[id^='"+idStart+"']");x.each(function(index,domEle){$(this).removeProp("checked");});}function selectFather(id){$("#"+id).prop("checked", "checked");}function UnSelectFather(id){$("#"+id).removeProp("checked");}//判断还有没被选中的checkedboxfunction isExistSelect(idStart){var flag = false;var $arrayEle=$("input[id^='"+idStart+"'][id!='"+idStart+"_"+idStart+"']");for (var i=0; i<$arrayEle.length; i++){if ($($arrayEle[i]).prop("checked")){flag=true;}}return flag;}function goSelect(id){var arrayVal=id.split("_");if (arrayVal[0] == arrayVal[1]){//parent domif ($("#"+id).prop("checked")){selectAll(arrayVal[0]);}else{unSelectAllBox(arrayVal[0]);}}else{//child domif ($("#" + id).prop("checked")) {selectFather(arrayVal[0] + "_" + arrayVal[0]);}else {if (!isExistSelect(arrayVal[0])){UnSelectFather(arrayVal[0] + "_" + arrayVal[0]);}}}}</script>  </head>    <body>      <fieldset>  <legend><input type="checkbox"  id="company_company" onclick="goSelect(this.id)" />客户管理</legend>    <div><input type="checkbox"  id="company_base"  onclick="goSelect(this.id)"/>客户管理1</div><div><input type="checkbox"  id="company_linkman" onclick="goSelect(this.id)" />客户管理2</div><div><input type="checkbox"  id="company_linkTouch"  onclick="goSelect(this.id)"/>客户管理3</div><div><input type="checkbox"  id="company_rule"  onclick="goSelect(this.id)"/>客户管理4</div></fieldset><br/><fieldset>  <legend><input type="checkbox"  id="employee_employee" onclick="goSelect(this.id)" />员工管理</legend>    <div><input type="checkbox"  id="employee_base"  onclick="goSelect(this.id)"/>员工管理1</div><div><input type="checkbox"  id="employee_linkman" onclick="goSelect(this.id)" />员工管理2</div><div><input type="checkbox"  id="employee_linkTouch"  onclick="goSelect(this.id)"/>员工管理3</div><div><input type="checkbox"  id="employee_rule"  onclick="goSelect(this.id)"/>员工管理4</div></fieldset>  </body></html>

note:本例中获取节点属性用的是prop()方法，用attr()不行。，jquery 1.6版本就对这两个方法进行了改变，attribute 表示从文档中获取DOM状态信息，而properties 表示元素的动态状态信息，比如说复选框的使用。

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