[LeetCode] Length of Last Word

来源:互联网 发布:刷奥币软件 编辑:程序博客网 时间:2024/06/02 19:24
Total Accepted: 9937 Total Submissions: 35192

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

public class Solution {    public int lengthOfLastWord(String s) {        int index =  s.length() - 1;        int len = 0;                while (index >= 0 && s.charAt(index) == ' ') index--;                while (index >= 0 && s.charAt(index) != ' ') {index--; len++;}                return len;    }}


public class Solution {    public int lengthOfLastWord(String s) {        int len = 0;                for (int i = 0; i < s.length(); i++) {            if (s.charAt(i) != ' ') {                if (i > 0 && s.charAt(i - 1) == ' ') len = 0;                len++;            }        }                return len;    }}

0 0
原创粉丝点击