OpenGL 矩阵变换机理

来源：互联网发布：一张银行卡能开淘宝吗编辑：程序博客网时间：2024/06/10 08:50
#include<math.h>#include "matrix.h"#define Pi 3.1415926void Proxy::Translate(float x, float y, float z){int i, j;bb[0][0] = 1; bb[0][1] = 0; bb[0][2] = 0; bb[0][3] = x;bb[1][0] = 0; bb[1][1] = 1; bb[1][2] = 0; bb[1][3] = y;bb[2][0] = 0; bb[2][1] = 0; bb[2][2] = 1; bb[2][3] = z;bb[3][0] = 0; bb[3][1] = 0; bb[3][2] = 0; bb[3][3] = 1;cc[0][0] = 0; cc[0][1] = 0; cc[0][2] = 0; cc[0][3] = 0;for(i = 0; i<4; i++)for(j = 0; j<4; j++){cc[i][0] += bb[i][j]*aa[j][0];}//数组cc转化为坐标Pos[0] = cc[0][0];Pos[1] = cc[1][0]; Pos[2] = cc[2][0];aa[0][0] = Pos[0];aa[1][0] = Pos[1];aa[2][0] = Pos[2];aa[3][0] = 1.0;}void Proxy::Scale(float x, float y, float z){int i, j;bb[0][0] = x; bb[0][1] = 0; bb[0][2] = 0; bb[0][3] = 0;bb[1][0] = 0; bb[1][1] = y; bb[1][2] = 0; bb[1][3] = 0;bb[2][0] = 0; bb[2][1] = 0; bb[2][2] = z; bb[2][3] = 0;bb[3][0] = 0; bb[3][1] = 0; bb[3][2] = 0; bb[3][3] = 1;cc[0][0] = 0; cc[0][1] = 0; cc[0][2] = 0; cc[0][3] = 0;for(i = 0; i<4; i++)for(j = 0; j<4; j++){cc[i][0] += bb[i][j]*aa[j][0];}//数组cc转化为坐标Pos[0] = cc[0][0];Pos[1] = cc[1][0]; Pos[2] = cc[2][0];aa[0][0] = Pos[0];aa[1][0] = Pos[1];aa[2][0] = Pos[2];aa[3][0] = 1.0;}void Proxy::Rotate(float angle, float x, float y, float z){int i, j;bb[0][0] = x*x + (float)cos(angle/180.0*Pi)*(1.0 - x*x);bb[0][1] = x*y*(1-(float)cos(angle/180.0*Pi))-z*(float)sin(angle/180.0*Pi); bb[0][2] = x*z*(1-(float)cos(angle/180.0*Pi))+y*(float)sin(angle/180.0*Pi);bb[0][3] = 0;bb[1][0] = x*y*(1-(float)cos(angle/180.0*Pi))+z*(float)sin(angle/180.0*Pi);bb[1][1] = y*y + (float)cos(angle/180.0*Pi)*(1.0 - y*y);bb[1][2] = y*z*(1-(float)cos(angle/180.0*Pi))-x*(float)sin(angle/180.0*Pi); bb[1][3] = 0;bb[2][0] = z*x*(1-(float)cos(angle/180.0*Pi))-y*(float)sin(angle/180.0*Pi); bb[2][1] = z*y*(1-(float)cos(angle/180.0*Pi))+x*(float)sin(angle/180.0*Pi); bb[2][2] = z*z + (float)cos(angle/180.0*Pi)*(1.0 - z*z);bb[2][3] = 0;bb[3][0] = 0; bb[3][1] = 0; bb[3][2] = 0; bb[3][3] = 1;cc[0][0] = 0; cc[0][1] = 0; cc[0][2] = 0; cc[0][3] = 0;for(i = 0; i<4; i++)for(j = 0; j<4; j++){cc[i][0] += bb[i][j]*aa[j][0];}//数组cc转化为坐标Pos[0] = cc[0][0];Pos[1] = cc[1][0]; Pos[2] = cc[2][0];aa[0][0] = Pos[0];aa[1][0] = Pos[1];aa[2][0] = Pos[2];aa[3][0] = 1.0;}
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