DevExpress之TreeList的研究绑定XML文件

来源：互联网发布：软件项目管理期末试卷编辑：程序博客网时间：2024/06/02 08:32

上次的递归调用进行对XML文件读取限制比较大，这次静态进行读取，思路还是先把XML读取到DataTable中然后进行绑定，代码入下：

   private DataTable CreatTable()        {            DataTable dt = new DataTable();            dt.Columns.Add("ID");            dt.Columns.Add("ParentID");            dt.Columns.Add("Name");            XmlDocument xmlDoc=new XmlDocument();            xmlDoc.Load(g_filepath);            XmlNode rootnode = xmlDoc.DocumentElement;            dr = dt.NewRow();            int Id = 1;            dr["ID"] = Id++;            dr["ParentID"] = 0;            dr["Name"] = rootnode.Name.ToString();            dt.Rows.Add(dr);            if (rootnode.HasChildNodes)            {                XmlNodeList xmlnodelist = rootnode.ChildNodes;                foreach (XmlNode xmlnode in xmlnodelist)                {                    dr = dt.NewRow();                    dr["ID"] = Id++;                    dr["ParentID"] = 1;                    dr["Name"] = xmlnode.Name.ToString();                    dt.Rows.Add(dr);                    if (xmlnode.HasChildNodes)                    {                        int j = 1;                        XmlNodeList nodelist = xmlnode.ChildNodes;                        foreach (XmlNode node in nodelist)                        {                            int pId=Id;                            dr = dt.NewRow();                            dr["ID"] = Id++;                            dr["ParentID"] =pId-j ;                            dr["Name"] =node.Name.ToString();                            dt.Rows.Add(dr);                            j++;                            if (node.HasChildNodes)                            {                                int i = 1;                                XmlNodeList list = node.ChildNodes;                                foreach (XmlNode Node in list)                                {                                    if (Node.NodeType == XmlNodeType.Text)                                    {                                        continue;                                    }                                    else                                    {                                        int ppId = Id;                                        dr = dt.NewRow();                                        dr["ID"] = Id++;                                        dr["ParentID"] = ppId - i;                                        dr["Name"] = Node.Name.ToString();                                        dt.Rows.Add(dr);                                        i++;                                        j++;                                    }                                }                            }                            else                            {                                continue;                            }                        }                    }                    else                    {                        continue;                    }                }            }            return dt;        }

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