ios程序异常退出时，发送邮件告知

1，首先在delegate文件里面- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions函数里面添加：
[plain] view plaincopy
NSSetUncaughtExceptionHandler (&UncaughtExceptionHandler);  

2，实现捕捉到异常时调用的函数（在@implementation之上）：
[plain] view plaincopy
void UncaughtExceptionHandler(NSException *exception) {  
 NSArray *arr = [exception callStackSymbols];  
 NSString *reason = [exception reason];  
 NSString *name = [exception name];  
    
 NSString *urlStr = [NSString stringWithFormat:@"mailto://[e-mail]?subject=bug报告&body=xxx项目报告!<br><br><br>"  
      "错误详情:<br>%@<br>--------------------------<br>%@<br>---------------------<br>%@",  
      name,reason,[arr componentsJoinedByString:@"<br>"]];  
    
 NSURL *url = [NSURL URLWithString:[urlStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];  
 [[UIApplication sharedApplication] openURL:url];  
    NSLog(@"%@",url);  
}