Children of the Candy Corn DFS+BFS
来源:互联网 发布:mac上安装nodejs 编辑:程序博客网 时间:2024/06/03 01:00
终于AC了,WA了一下午,各种错误,人品确实有问题,最终看了题解,对着题解又找了好久的错,在此要感谢http://blog.csdn.net/lyy289065406/article/details/6647668的详细题解。
题目大意:
在一个迷宫的S到E,求一直往左优先走和一直往右走优先以及最短路所经过的格子数。
#include <stdio.h>#include <stdlib.h>typedef struct{int y,x;int depth;}SE;SE s, e;//起止点;int map[42][42];int lsteps;int rsteps;void DFS_LF(int i,int j,int d){//当前位置的行,列和方向;++lsteps;if(i==e.y&&j==e.x) return ;switch(d){//左优先 1032case 0: {if(map[i][j-1])DFS_LF(i,j-1,1);else if(map[i-1][j])DFS_LF(i-1,j,0);else if(map[i][j+1])DFS_LF(i,j+1,3);else if(map[i+1][j])DFS_LF(i+1,j,2);break;}case 1: {//左优先 2103if(map[i+1][j])DFS_LF(i+1,j,2);else if(map[i][j-1])DFS_LF(i,j-1,1);else if(map[i-1][j])DFS_LF(i-1,j,0);else if(map[i][j+1])DFS_LF(i,j+1,3);break;}case 2: {//3210if(map[i][j+1])DFS_LF(i,j+1,3);else if(map[i+1][j])DFS_LF(i+1,j,2);else if(map[i][j-1])DFS_LF(i,j-1,1);else if(map[i-1][j])DFS_LF(i-1,j,0);break;}case 3: {//左优先 0321if(map[i-1][j])DFS_LF(i-1,j,0);else if(map[i][j+1])DFS_LF(i,j+1,3);else if(map[i+1][j])DFS_LF(i+1,j,2);else if(map[i][j-1])DFS_LF(i,j-1,1);break;}}return ;}void DFS_RF(int i,int j,int d){ ++rsteps; if(i==e.y&&j==e.x) return; switch(d) { case 0: { if(map[i][j+1]) DFS_RF(i,j+1,3); else if(map[i-1][j]) DFS_RF(i-1,j,0); else if(map[i][j-1]) DFS_RF(i,j-1,1); else if(map[i+1][j]) DFS_RF(i+1,j,2); break; } case 1: { if(map[i-1][j]) DFS_RF(i-1,j,0); else if(map[i][j-1]) DFS_RF(i,j-1,1); else if(map[i+1][j]) DFS_RF(i+1,j,2); else if(map[i][j+1]) DFS_RF(i,j+1,3); break; } case 2: { if(map[i][j-1]) DFS_RF(i,j-1,1); else if(map[i+1][j]) DFS_RF(i+1,j,2); else if(map[i][j+1]) DFS_RF(i,j+1,3); else if(map[i-1][j]) DFS_RF(i-1,j,0); break; } case 3: { if(map[i+1][j]) DFS_RF(i+1,j,2); else if(map[i][j+1]) DFS_RF(i,j+1,3); else if(map[i-1][j]) DFS_RF(i-1,j,0); else if(map[i][j-1]) DFS_RF(i,j-1,1); break; } } return;}void BFS_MIN(int i,int j){int visit[42][42]={0};SE queue[1700];//队列int head=0,tail=0;queue[head].y=i;queue[tail].x=j;queue[tail++].depth=1;visit[i][j]=1;while(head<tail){SE tmp=queue[head++];if(tmp.y==e.y&&tmp.x==e.x){printf("%d\n",tmp.depth);return;}if(map[tmp.y-1][tmp.x]&&!visit[tmp.y-1][tmp.x]){visit[tmp.y-1][tmp.x]=1;queue[tail].y=tmp.y-1;//入队queue[tail].x=tmp.x;queue[tail++].depth=tmp.depth+1;}if(map[tmp.y][tmp.x-1]&&!visit[tmp.y][tmp.x-1]){visit[tmp.y][tmp.x-1]=1;queue[tail].y=tmp.y;queue[tail].x=tmp.x-1;queue[tail++].depth=tmp.depth+1;}if(map[tmp.y+1][tmp.x]&&!visit[tmp.y+1][tmp.x]){visit[tmp.y+1][tmp.x]=1;queue[tail].y=tmp.y+1;queue[tail].x=tmp.x;queue[tail++].depth=tmp.depth+1;}if(map[tmp.y][tmp.x+1]&&!visit[tmp.y][tmp.x+1]){visit[tmp.y][tmp.x+1]=1;queue[tail].y=tmp.y;queue[tail].x=tmp.x+1;queue[tail++].depth=tmp.depth+1;}}return;}int main(){//freopen("fang.in","r",stdin);//freopen("fang.out","w",stdout);int i, j, direction;int w,h;int test;scanf("%d", &test);while (test--){scanf("%d%d", &w,&h);//memset(map, 0, sizeof(map));for(i=0;i<=h;i++)for(j=0;j<=w;j++)map[i][j]=0;lsteps=1;rsteps=1;for (i = 1; i <= h; i++)for (j = 1; j <= w; j++){char tmp;scanf(" %c", &tmp);if (tmp == 'S'){s.y = i;s.x = j;map[i][j] = 1;if (h == i)direction = 0;else if (1 == i)direction = 2;else if (1 == j)direction = 3;else if (w == j)direction = 1;}else if (tmp == 'E'){e.y = i;e.x = j;map[i][j] = 1;}else if (tmp == '.'){map[i][j] = 1;}}switch (direction){case 0:{ DFS_LF(s.y-1,s.x,0); break;}case 1:{ DFS_LF(s.y,s.x-1,1); break;}case 2:{ DFS_LF(s.y+1,s.x,2);break;}case 3:{ DFS_LF(s.y,s.x+1,3); break;}}printf("%d ",lsteps);switch(direction){case 0:{DFS_RF(s.y-1,s.x,0);break;}case 1:{DFS_RF(s.y,s.x-1,1);break;}case 2:{DFS_RF(s.y+1,s.x,2);break;}case 3:{DFS_RF(s.y,s.x+1,3);break;}}printf("%d ",rsteps);BFS_MIN(s.y,s.x);}return 0;}
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