求利润数额

/* * Copyright (c) 2013, 烟台大学计算机学院* All rights reserved.* 作    者：王颖* 完成日期：2013 年  10  月 28 日* 版 本 号：v1.0** 输入描述： 无* 问题描述：求利润数额* 程序输出：* 问题分析：（用switch语句完成）* 算法设计：略*/#include <iostream>using namespace std;int main(){    int t,l,sum;    cout<<"请输入利润数额：";    cin>>l;    t=l/100000;    if (t>=10)    {    sum=1*0.1+1*0.075+2*0.05+2*0.03+4*0.015+(l-10)*0.01;    cout <<"sum="<<sum;    }    else    {    switch(t)    {    case 0:sum=l*0.1;    cout<<"sum="<<sum;break;    case 1:sum=1*0.1+(l-1)*0.075;    cout<<"sum="<<sum;    case 2:sum=1*0.1+(l-1)*0.075;    cout<<"sum="<<sum;break;    case 3:sum=1*0.1+1*0.075+(l-2)*0.05;    cout<<"sum="<<sum;    case 4:sum=1*0.1+1*0.075+(l-2)*0.05;    cout<<"sum="<<sum;break;    case 5:sum=1*0.1+1*0.075+2*0.05+(l-4)*0.03;    cout<<"sum="<<sum;    case 6:sum=1*0.1+1*0.075+2*0.05+(l-4)*0.03;    cout<<"sum="<<sum;break;    case 7:sum=1*0.1+1*0.075+2*0.05+2*0.03+(l-6)*0.015;    cout<<"sum="<<sum;break;    case 8:sum=1*0.1+1*0.075+2*0.05+2*0.03+(l-6)*0.015;    cout<<"sum="<<sum;break;    case 9:sum=1*0.1+1*0.075+2*0.05+2*0.03+(l-6)*0.015;    cout<<"sum="<<sum;break;    default:cout<<"error!";break;    }    }    return 0;}