面试题45：圆圈中最后剩下的数字

题目：0,1，...，n-1这n个数字排成一个圆圈，从数字0开始每次从这个圆圈里删除第m个数字，求出这个圆圈里剩下的最后一个数字

常规思路：主要list的运用

代码：

#include <iostream> #include <list> using namespace std;int LastRemaining(unsigned int n,unsigned int m){if(n<1 || m<1)return -1;unsigned int i;list<int> numbers;for(i=0;i<n;++i)numbers.push_back(i);list<int>::iterator current=numbers.begin();while(numbers.size() >1){for(int i=1;i<m;i++){current ++;if(current == numbers.end())current=numbers.begin();}list<int>::iterator next=++current;if(next == numbers.end())next=numbers.begin();--current;numbers.erase(current);current=next;}return *(current);}void main(){int result=LastRemaining(5,3);printf("%d\n",result);}

结果：

3
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