poj3461(KMP)
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Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A','B','C', …, 'Z'} and two finite strings over that alphabet, a wordW and a textT, count the number of occurrences of W inT. All the consecutive characters of W must exactly match consecutive characters ofT. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
- One line with the word W, a string over {'A', 'B','C', …,'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the stringW).
- One line with the text T, a string over {'A', 'B','C', …,'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the wordW in the textT.
Sample Input
3BAPCBAPCAZAAZAZAZAVERDIAVERDXIVYERDIAN
Sample Output
130
Source
#include<iostream>#include<cstdio>#include<cstring>using namespace std;char W[10010],T[1000010];//W为模式串,T为主串int next[10010];//KMP算法中计算next[]数组void getNext(char *p){ int j,k,len=strlen(p); j=0; k=-1; next[0]=-1; while(j<len) { if(k==-1||p[j]==p[k]) { next[++j]=++k; } else k=next[k]; }}//KMP算法统计模式串W在主串T中出现的次数int KMP_count(char *W,char *T){ int i,wlen=strlen(W),tlen=strlen(T),j=0,ans=0; getNext(W); for(i=0;i<tlen;i++) { while(j>0&&T[i]!=W[j]) j=next[j]; if(W[j]==T[i])j++; if(j==wlen) { ans++; j=next[j]; } } return ans;}int main(){ int tcase; scanf("%d",&tcase); while(tcase--) { scanf("%s%s",&W,&T); strlen(W); strlen(T); printf("%d\n",KMP_count(W,T)); } return 0;}
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