uva 10051

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将每一个分解为六个两面的 简单地dp 回溯输出路径.....

#include <cstdio>#include <cstring>#include <cmath>#include <algorithm>using namespace std;struct cc{    int top,bom,fa,w;    void f(int a, int b, int c, int d)    {        top = a;        bom = b;        fa = c;        w = d;    }};cc cube[3100];char face[7][10] = { "front","back", "left", "right", "top", "bottom"};int dp[3100],cu[7],p[3100];void printpath(int k){    if(k == -1)        return ;    printpath(p[k]);    printf("%d %s\n",cube[k].w, face[cube[k].fa]);}int main(){    int n, ca = 1;    while(scanf("%d", &n) == 1 && n)    {        int m = 0;        for(int i = 0; i < n; i++)        {            for(int j = 0; j < 6; j++)                scanf("%d",&cu[j]);            for(int j = 0; j < 6; j++)            {                cube[m++].f(cu[j], j%2 == 1?cu[j-1]:cu[j+1], j, i+1);            }        }        memset(dp, 0, sizeof( dp));        memset(p, -1, sizeof( p));        int _max = 0, k;        for(int i = 0; i < m; i++)            for(int j = i+1; j < m; j++)                if(cube[j].w > cube[i].w && cube[i].bom == cube[j].top && dp[j] < dp[i]+1)                {                    dp[j] = dp[i]+1;                    p[j] = i;                    if(dp[j] > _max)                    {                        _max = dp[j];                        k = j;                    }                }        printf("Case #%d\n%d\n",ca++,_max+1);        printpath(k);        puts("");    }    return 0;}