hdu 1850 尼姆博弈

#include<cstdio>#include<algorithm>using namespace std;#define N 100+10int main(){    //freopen("game.in","r",stdin); freopen("game.out","w",stdout);    int heapnum,heap[N];    while(scanf("%d",&heapnum)!=EOF && heapnum)    {        int sum=0,ans=0;        for(int i=1;i<=heapnum;i++)        {            scanf("%d",&heap[i]); sum^=heap[i];        }        for(int i=1;i<=heapnum;i++)        {            if(heap[i]>(sum^heap[i])) ans++;//大于号的优先级要高于异或运算！        }        printf("%d\n",ans);    }    return 0;}

声明：这代码不是俺写的，本人的意思只是若是比赛遇到相同的题，这代码可以派些用场，嗯，就这么个意思