面试题汇集(更新中)

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1,求较小和较大的值,不能用 比较运算符 if-else ?: while for 内嵌汇编 递归 第三方函数
int Min(int a, int b)                          int Min(int a, int b)       
{                                                         {

  //write code here                            //write code here  
}                                                          }
解答:

int max = ((a+b)+abs(a-b))/2

int min((a+b)-abs(a-b))/2;

2,写atol()函数

#include <stdio.h>
int main()
{
    unsigned char *nptr;
    char a[] =" -12345";
    int c; /* current char */
    long total; /* current total */
    int sign; /* if '-', then negative, otherwise positive */

    nptr = a;
    /* skip whitespace */
    while ( isspace((int)(unsigned char)*nptr) )
        ++nptr;

    c = (int)(unsigned char)*nptr++; /*符号*/
    sign = c; /* save sign indication */
    if (c == '-' || c == '+'){
        c = (int)(unsigned char)*nptr++; /* skip sign */
        printf("%d\n",c);
    }
     total = 0;

     while (isdigit(c)) {
        total = 10 * total + (c - '0'); /* accumulate digit */
        c = (int)(unsigned char)*nptr++; /* get next char */
     }
     if (sign == '-'){
        total = -total;
        printf("total = %d\n",total);
     }else
        //return total; /* return result, negated if necessary */
        printf("total = %d\n",total);
     return 0;
}

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