poj1102——LC-Display

模拟题。运用七段数码显示。参考：http://hi.baidu.com/%8E%E1%D0%B3/blog/item/0846471b6ccf8371dab4bd9a.html

#include<iostream>#include<cstdio>#include<string>using namespace std;char n1[11]={"- -- -----"}; //笔画1被数字0,2,3,5,6,7,8,9覆盖char n2[11]={"| ||| ||"}; //笔画2被数字0,4,5,6,8,9覆盖char n3[11]={"||||| |||"}; //笔画3被数字0,1,2,3,4,7,8,9覆盖char n4[11]={" ----- --"}; //笔画4被数字2,3,4,5,6,8,9覆盖char n5[11]={"| | | | "}; //笔画5被数字0,2,6,8覆盖char n6[11]={"|| |||||||"}; //笔画6被数字0,1,3,4,5,6,7,8,9覆盖char n7[11]={"- -- -- --"}; //笔画7被数字0,2,3,5,6,8,9覆盖int s;char dig[100];int main(){int i,j,len,k;while(scanf("%d%s",&s,dig)&&s){len=strlen(dig);for(i=0;i<len;i++){printf(" ");int num=dig[i]-'0';for(j=0;j<s;j++)printf("%c",n1[num]);printf(" ");}printf("/n");for(i=0;i<s;i++){for(j=0;j<len;j++){int num=dig[j]-'0';printf("%c",n2[num]);for(k=0;k<s;k++)printf(" ");printf("%c",n3[num]);printf(" ");}printf("/n");}for(i=0;i<len;i++){printf(" ");int num=dig[i]-'0';for(j=0;j<s;j++)printf("%c",n4[num]);printf(" ");}printf("/n");for(i=0;i<s;i++){for(j=0;j<len;j++){int num=dig[j]-'0';printf("%c",n5[num]);for(k=0;k<s;k++)printf(" ");printf("%c",n6[num]);printf(" ");}printf("/n");}for(i=0;i<len;i++){printf(" ");int num=dig[i]-'0';for(j=0;j<s;j++)printf("%c",n7[num]);printf(" ");}printf("/n/n");}return 0;}