LeetCode 371. Sum of Two Integers
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题意
在不使用加号(+)、减号(-)的情况下计算a+b。
解题思路
a&b可以得到进位信息。
a^b可以得到不进位情况下的a+b。
所以模拟一下进位就好。
参考代码
// javapublic class Solution { public int getSum(int a, int b) { while (true){ int tempa = (a & b) << 1; int tempb = a ^ b; a = tempa; b = tempb; if (a == 0) break; } return b; }}
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