2018届秋招提前批阿里在线编程

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/*幼儿园有10个小朋友,把1 – 20中所有奇数数字的卡片分别发给这10个小朋友。集合的时候小朋友们排成一排,组成一个由数字组成的字符串,如59731315….11917,但是老师发现少了一个小朋友,你能帮忙找出少掉的那个小朋友吗?1 3 5 7 9 11 13 15 17 19// 1 7// 3 2// 5 2// 7 2// 9 2思路:遍历字符串,统计出1 3 5 7 9的个数;  判断1 3 5 7 9 出现的个数。*/#include <iostream>int findBoy(char* arr) {int num_1 = 0;int num_3 = 0;int num_5 = 0;int num_7 = 0;int num_9 = 0;int result = -1;char* cur = arr;while (*cur != '\0') {int num = *cur - '0';if (num == 1) {++num_1;}else if (num == 3) {++num_3;}else if (num == 5) {++num_5;}else if (num == 7) {++num_7;}else if (num == 9) {++num_9;}++cur;}if (num_1 == 6) {//少了一个1if (num_3 == 1) {result = 13;}else if (num_5 == 1) {result = 15;}else if (num_7 == 1) {result = 17;}else if (num_9 == 1) {result = 19;}else{result = 1;}}else if (num_1 == 5) {//11result = 11;}else if (num_3 == 1) {//3result = 3;}else if (num_5 == 1) {result = 5;}else if (num_7 == 1) {result = 7;}else if (num_9 == 1) {result = 9;}return result;}void main(){std::cout << findBoy("15971913151117");std::cin.get();}

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