项目32-警察与厨师

来源：互联网发布：c语言中void的例题编辑：程序博客网时间：2024/06/03 14:03

（1）根据下面的类图，定义各个类：
这里写图片描述

要求：
各个成员函数，只要输出相关的信息即可，暂不深究其业务功能
请为各个类增加构造函数
在实现中，可以增加需要的其他函数

自行编制main函数，完成初步的测试

运行代码：

#include <iostream>using namespace std;class Person{public:    Person(int, string);    void action();    string getName()    {        return name;    }private:    int age;    string name;};Person::Person(int a, string n):age(a), name(n) {}void Person::action(){    cout<<name<<" do some action"<<endl;}class Police: public Person{public:    Police(int, string, int);    void arrest(Person);private:    int level; //级别};Police::Police(int a, string n, int l):Person(a,n),level(l) {}void Police::arrest(Person p){    cout<<" Police "<<getName()<<" arrest " <<p.getName()<<endl;}class Cook: public Person{public:    Cook(int, string, double);    void getCake(int);private:    double salary; //薪水};Cook::Cook(int a, string n, double s):Person(a,n),salary(s) {}void Cook::getCake(int n){    cout<<" Cook "<<getName()<<" gave me " <<n<<" cakes."<<endl;}int main(){    Person tom(120,"Tom");    Police jack(30,"Jack",2);    Cook john(24,"John",5000);    jack.arrest(tom);    john.getCake(4);    return 0;}

运行结果：

（2）下面的类图，为Polic类和Cook类增加了对象成员，请扩充代码，完成上述各项要求
这里写图片描述

代码（2）：

#include <iostream>using namespace std;class Person{public:    Person(int, string);    void action();    string getName(){return name;}private:    int age;    string name;};Person::Person(int a, string n):age(a), name(n) {}void Person::action(){    cout<<name<<endl;}class Police: public Person{public:    Police(int a, string n, int l, int la, string ln);    void arrest(Person);    void show();private:    int level;    Person leader;};Police::Police(int a, string n, int l, int la, string ln):Person(a,n),level(l),leader(la,ln) {}void Police::arrest(Person p){    cout<<"Police "<<getName()<<" arrest " <<p.getName()<<endl;}void Police::show(){    cout<<"Police "<<getName()<<", leader is " <<leader.getName()<<endl;}class Cook: public Person{public:    Cook(int a, string n, double s,int pa, string pn, int pl, int pla, string pln);    void getCake(int);    void show();private:    double salary;    Police protector;};Cook::Cook(int a, string n, double s,int pa, string pn, int pl, int pla, string pln):    Person(a,n),salary(s),protector(pa,pn,pl,pla,pln) {}void Cook::getCake(int n){    cout<<"Cook "<<getName()<<" gave me " <<n<<" cakes."<<endl;}void Cook::show(){    cout<<"Cook "<<getName()<<" is protected by Police "<<protector.getName()<<endl;}int main(){    Person tom(120,"Tom");    Police jack(30,"Jack",2,43,"Jerry");    Cook john(24,"John",5000,30,"Jack",2,43,"Jerry");    jack.show();    john.show();    return 0;}

运行结果：

学习心得：每个派生类的构造函数都要继承积累构造函数中的参数，不可缺少，另外注意积累中参数的访问方式。

0 0