zoj1251

来源:互联网 发布:c语言中字符串处理函数 编辑:程序博客网 时间:2024/06/08 02:48

不难。


#include <iostream>using namespace std;int main(){    int num,time = 0;    while(cin >> num && num)    {        time++;        int blocks[50],sum = 0,block = 0;        for(int m = 0;m < num;m++)        {            cin >> blocks[m];            sum += blocks[m];        }        sum /= num;        for(int m = 0;m < num;m++)            if(blocks[m] > sum)                block += blocks[m] - sum;        cout << "Set #" << time << endl;        cout << "The minimum number of moves is " << block << "." << endl << endl;;    }    return 0;}


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