错误sql

来源:互联网 发布:北京行知打工子弟学校 编辑:程序博客网 时间:2024/06/08 10:24
SELECT to_char(to_date('2012-12-26 22:22:44', 'yyyy-mm-dd hh24:mi:ss'),
               'MMDDYYYY:HH24:MI:SS') date1,
       to_char(to_date('2012-12-27 22:22:44', 'yyyy-mm-dd hh24:mi:ss'),
               'MMDDYYYY:HH24:MI:SS') date2,
         
       
       trunc(86400 * (date2 - date1)) - 60 * trunc(86400 * (date2 - date1) / 60) seconds,
         
       
       trunc(86400 * (date2 - date1) / 60) - 60 * trunc(86400 * (date2 - date1) / 60 / 60) minutes,
         
       
       trunc(86400 * (date2 - date1) / 60 / 60) - 24 * trunc(86400 * (date2 - date1) / 60 / 60 / 24) hours,
         
       
       trunc(86400 * (date2 - date1) / 60 / 60 / 24) days ,
       
       trunc(86400 * (date2 - date1) / 60 / 60 / 24 / 7) weeks  


  FROM dual;



SELECT '06/20/2003:16:55:14:000000' time1, '07/08/2003:11:22:57:000000' time2,  


substr((time2-time1),instr((time2-time1),' ')+7,2)   seconds,  


substr((time2-time1),instr((time2-time1),' ')+4,2)   minutes,  


substr((time2-time1),instr((time2-time1),' ')+1,2)   hours,  


trunc(to_number(substr((time2-time1),1,instr(time2-time1,' '))))  days,  


trunc(to_number(substr((time2-time1),1,instr(time2-time1,' ')))/7) weeks


FROM dual;



SELECT   
       
      60 * trunc(86400 * (date2 - date1) / 60) seconds,
         
       
       trunc(86400 * (date2 - date1) / 60) - 60 * trunc(86400 * (date2 - date1) / 60 / 60) minutes,
         
       
       trunc(86400 * (date2 - date1) / 60 / 60) - 24 * trunc(86400 * (date2 - date1) / 60 / 60 / 24) hours,
         
       
       trunc(86400 * (date2 - date1) / 60 / 60 / 24) days ,
       
       trunc(86400 * (date2 - date1) / 60 / 60 / 24 / 7) weeks  




  FROM ( select to_date('2012-12-26 22:22:42', 'yyyy-mm-dd hh24:mi:ss') date1, 
     to_date('2012-12-27 22:22:44', 'yyyy-mm-dd hh24:mi:ss') date2 from dual) s
       

http://www.cnblogs.com/lz-cswb/archive/2012/04/29/2476329.html